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Oscillations

JEE Main 2024 (Online) 6th April Morning ShiftNumericalEasy📈 Topic in 16% papers+4
Ques. 1JEE Main 2024, 6 April (Morning Shift)

A particle is doing simple harmonic motion of amplitude 0.06 m and time period 3.14 s. The maximum velocity of the particle is cm/s.

Answer

12

Solution

vmax = A = A 2 T

= 0.06 2 3.143.14 = 0.12 m/s

= 12 cm/s

Answer: 12

Keep practising — Oscillations

Ques. 2JEE Main 2024, 4 April (Evening Shift)

In simple harmonic motion, the total mechanical energy of given system is E. If mass of oscillating particle P is doubled then the new energy of the system for same amplitude is: [figure]

  1. E/ 2
  2. 2E
  3. E 2
  4. E
Ques. 3JEE Main 2024, 4 April (Evening Shift)

The displacement of a particle executing SHM is given by x = 10 ( t + 3 ) m. The time period of motion is 3.14 s. The velocity of the particle at t = 0 is m/s.

Ques. 4JEE Main 2024, 1 February (Evening Shift)

A mass m is suspended from a spring of negligible mass and the system oscillates with a frequency f1. The frequency of oscillations if a mass 9 m is suspended from the same spring is f2. The value of f1f2 is .

Ques. 5JEE Main 2024, 31 January (Morning Shift)

A particle performs simple harmonic motion with amplitude A. Its speed is increased to three times at an instant when its displacement is 2A3. The new amplitude of motion is nA3. The value of n is .

Ques. 6JEE Main 2024, 31 January (Evening Shift)

The time period of simple harmonic motion of mass M in the given figure is M5k, where the value of is . [figure]

Ques. 7JEE Main 2024, 30 January (Evening Shift)

A simple pendulum is placed at a place where its distance from the earth's surface is equal to the radius of the earth. If the length of the string is 4 m, then the time period of small oscillations will be s. [take g= 2 m s-2]

Ques. 8JEE Main 2024, 29 January (Morning Shift)

When the displacement of a simple harmonic oscillator is one third of its amplitude, the ratio of total energy to the kinetic energy is x8, where x= .

Ques. 9JEE Main 2024, 29 January (Evening Shift)

A simple harmonic oscillator has an amplitude A and time period 6 second. Assuming the oscillation starts from its mean position, the time required by it to travel from x=A to x= 32 A will be x s, where x= .

Ques. 10JEE Main 2024, 27 January (Morning Shift)

A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, velocity of the particle is 10 cm/s. The distance of the particle from the mean position when its speed becomes 5 cm/s is cm, where = .

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