Let f(x) = cases -a & if -a x 0 \ x + a & if 0 < x a cases where a > 0 and g(x) = (f(|x|) - |f(x)|)/2. Then the function g : [-a, a] [-a, a] is
- neither one-one nor onto.
- both one-one and onto.
- one-one.
- onto
Answer
(1) neither one-one nor onto.
Solution
-a x < 0: f(|x|) = -x + a, |f(x)| = a g(x) = - x2
x = 0: f(0) = -a g(0) = -a - a2 = -a
0 < x a: f(|x|) = |f(x)| = x + a g(x) = 0
[figure]
g(x) = 0 for every x (0, a] g is not one-one
Range = \-a\ [0, a2 ] [-a, a] g is not onto
Answer: (1)