Which amongst the following options is correct graphical representation of Boyle's law?
- [figure]
- [figure]
- [figure]
- [figure]
Answer
(1) [figure]
Solution
Boyle's law: at constant temperature, PV = nRT = constant.
P = nRT 1V
A plot of P against 1V is a straight line through the origin with slope nRT, so the slope is larger at higher temperature: T3 line steepest when T3>T2>T1. This is option (1).
Option (2) is wrong: P vs 1V is not a curve.
Option (3) is a P vs T plot at constant volume (Gay-Lussac's law), not Boyle's law.
Option (4) is wrong: at higher temperature the P vs V isotherm lies farther from the axes, so T3 should be the outermost curve.
Answer: (1)