A vessel contains 3.2 g of dioxygen gas at STP (273.15 K and 1 atm pressure). The gas is now transferred to another vessel at constant temperature, where pressure becomes one third of the original pressure. The volume of new vessel in L is : (Given : molar volume at STP is 22.4 L)
- 67.2
- 6.72
- 2.24
- 22.4
Answer
(2) 6.72
Solution
Moles of O2 = 3.232 = 0.1 mol
Volume at STP, V1 = 0.1 22.4 = 2.24 L
At constant temperature (Boyle's law): p1V1 = p2V2, with p2 = p13
V2 = 3V1
= 3 2.24 = 6.72 L
Answer: (2)