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Application of Integrals · Question 23

JEE Main 2025 (Online) 4th April Morning ShiftNumericalMedium📈 Topic in 74% papers+4
1

If the area of the region \(x, y) : |x - 5| y 4 x\ is A, then 3A is equal to .

Answer

368

Solution

Intersections of y = 4 x with y = |x - 5| (put x = t):

x 5: t2 - 5 = 4t t2 - 4t - 5 = 0 t = 5 x = 25

x < 5: 5 - t2 = 4t t2 + 4t - 5 = 0 t = 1 x = 1

Between x = 1 and x = 25, 4 x |x - 5|.

A = 125 4 x dx - 125 |x - 5| dx

125 4 x dx = 83 [x3/2 ]125 = 83(125 - 1) = 9923

125 |x - 5| dx = 15 (5 - x) dx + 525 (x - 5) dx = 8 + 200 = 208

A = 9923 - 208 = 3683

3A = 368

Answer: 368

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2

A line passing through the point A(-2, 0) touches the parabola P: y2 = x - 2 at the point B in the first quadrant. The area of the region bounded by the line AB, parabola P and the x-axis, is :

  1. 3
  2. 73
  3. 83
  4. 2
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3

The area of the region bounded by the curve y = \|x|, x|x-2|\, the x-axis and the lines x = -2 and x = 4 is equal to

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4

The area of the region \(x, y) : |x - y| y 4 x\ is

  1. 5123
  2. 20483
  3. 512
  4. 10243
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5

If the area of the region \(x, y) : |4 - x2 | y x2, y 4, x 0 \ is ( 80 2 - ), , N, then + is equal to .

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6

Let the area of the region \(x, y) : 2y x2 + 3, y + |x| 3, y |x - 1|\ be A. Then 6A is equal to :

  1. 14
  2. 18
  3. 16
  4. 12
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7

The area (in sq. units) of the region \(x, y) : 0 y 2|x| + 1, 0 y x2 + 1, |x| 3\ is

  1. 323
  2. 643
  3. 173
  4. 803
JEE Main 2025 (Online) 28th January Morning Shift
8

The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:

  1. 4 - 13
  2. 2 - 13
  3. 2 ( 2 - 13 )
  4. 12 ( 2 - 13 )
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