How many different kinds of gametes will be produced by a plant having the genotype AABbCC?
- Two
- Nine
- Four
- Three
Answer
(1) Two
Solution
∵ Number of kinds of gametes = 2n, where n = number of heterozygous gene pairs.
⇒ In AABbCC only Bb is heterozygous (AA and CC are homozygous), so n = 1.
⇒ Number of gametes = 21 = 2, namely ABC and AbC.
Answer: (1)