Suppose that two chords, drawn from the point (1, 2) on the circle x2+y2+x-3y=0 are bisected by the y-axis. If the other ends of these chords are R and S, and the mid point of the line segment RS is ( , ), then 6( + ) is equal to :
- 1
- 3
- 4
- 6
Answer
(2) 3
Solution
(1, 2) lies on the circle: 1+4+1-6=0
A chord from (1, 2) bisected by the y-axis has mid-point (0, t), so its other end is (-1, 2t-2).
This end lies on the circle: 1+(2t-2)2-1-3(2t-2)=0
Put u=2t-2: u2-3u=0 u=0 or u=3
R =(-1, 0), S =(-1, 3)
Mid-point of RS = (-1, 32 ) + = 12
6( + )=3
Answer: (2)