Two identical bodies, projected with the same speed at two different angles cover the same horizontal range R. If the time of flight of these bodies are 5 s and 10 s, respectively, then the value of R is m. (Take g=10 m/s2)
- 250
- 25
- 500
- 125
Answer
(1) 250
Solution
[figure]
Equal ranges with the same speed angles of projection and (90 - )
T1= 2u g, T2= 2u (90 - )g= 2u g
T1T2= 4u2 g2= 2g u2 2 g= 2Rg
R= gT1T22= 10 5 102=250 m
Answer: (1)