The velocity of a particle is given as v=-x i+2y j-z k m/s. The magnitude of acceleration at point (1, 2, 4) is m/s2.
- 6
- 9
- 33
- 0
Answer
(2) 9
Solution
Each velocity component depends only on its own coordinate, so
ax= dvxdt= dvxdx dxdt=vx dvxdx (similarly for y, z)
ax=(-x)(-1)=x
ay=(2y)(2)=4y
az=(-z)(-1)=z
At (1, 2, 4): a=1 i+8 j+4 k
| a|= 12+82+42= 81
=9 m/s2
Answer: (2)