A boy throws a ball into air at 45 from the horizontal to land it on a roof of a building of height H. If the ball attains maximum height in 2 s and lands on the building in 3 s after launch, then value of H is m. (g = 10 m/s2)
- 20
- 25
- 10
- 15
Answer
(4) 15
Solution
Time to reach maximum height: t = u g = 2 s
u = 20 m/s
Vertical displacement after 3 s: H = (u )t - 12gt2
H = 20 3 - 12 10 32 = 60 - 45 = 15 m
Answer: (4)