Let A be a 3 3 matrix such that AT bmatrix1\ 0\ 1 bmatrix= bmatrix5\ 2\ 2 bmatrix, AT bmatrix0\ 0\ 1 bmatrix= bmatrix3\ 1\ 1 bmatrix, A bmatrix1\ 0\ 1 bmatrix= bmatrix3\ 4\ 4 bmatrix and A bmatrix0\ 0\ 1 bmatrix= bmatrix1\ 3\ 1 bmatrix. If (A)=1, then (adj (A2+A ) ) is equal to:
- 16
- 25
- 49
- 64
Answer
(4) 64
Solution
Let e1= bmatrix1\\0\\0 bmatrix, e3= bmatrix0\\0\\1 bmatrix. Then ATek = k-th row of A and Aek = k-th column of A.
ATe3=(3, 1, 1) R3=(3, 1, 1)
AT(e1+e3)=R1+R3=(5, 2, 2) R1=(2, 1, 1)
Ae3=C3=(1, 3, 1); A(e1+e3)=C1+C3=(3, 4, 4) C1=(2, 1, 3)
A= bmatrix2 & 1 & 1\ 1 & k & 3\ 3 & 1 & 1 bmatrix
A=2(k-3)-1(1-9)+1(1-3k)=3-k=1 k=2
A2+A=A(A+I), A+I= bmatrix3 & 1 & 1\ 1 & 3 & 3\ 3 & 1 & 2 bmatrix
(A+I)=3(6-3)-1(2-9)+1(1-9)=9+7-8=8
(A2+A )= A (A+I)=1 8=8
|adj M|=|M|n-1 with n=3
(adj (A2+A ) )=82=64
Answer: (4)