The sum of all possible values of [0, 2 ], for which the system of equations : x 3 -8y-12z=0 x 2 +3y+3z=0 x+y+3z=0 has a non-trivial solution, is equal to :
- 2
- 3
- 4
Answer
(4) 4
Solution
For a non-trivial solution, the determinant of the coefficients must be zero:
vmatrix 3 & -8 & -12\ 2 & 3 & 3\ 1 & 1 & 3 vmatrix=0
3 (9-3)+8(3 2 -3)-12( 2 -3)=0
6 3 +12 2 +12=0
3 +2 2 +2=0
Put c= : (4c3-3c )+2 (2c2-1 )+2=0
4c3+4c2-3c=0 c(2c-1)(2c+3)=0
=0 or = 12 ( =- 32 is not possible)
In [0, 2 ]: = 2, 3 2, 3, 5 3
Sum =2 +2 =4
Answer: (4)