One mole of Cl2(g) was passed into 2 L of cold 2 M KOH solution. After the reaction, the concentrations of Cl-, ClO- and OH- are respectively (assume volume remains constant)
- 0.5 M, 0.5 M, 0.5 M
- 1 M, 1 M, 1 M
- 0.5 M, 0.5 M, 1 M
- 0.75 M, 0.75 M, 1 M
Answer
(3) 0.5 M, 0.5 M, 1 M
Solution
With cold dilute alkali (NCERT):
Cl2 + 2OH- Cl- + ClO- + H2O
Moles of OH- = 2 2 = 4 mol; 1 mol Cl2 uses 2 mol OH-.
Cl- = 1 mol, ClO- = 1 mol, OH- left = 2 mol
In 2 L: [Cl-] = 0.5 M, [ClO-] = 0.5 M, [OH-] = 1 M
Answer: (3)