A stationary particle breaks into two parts of masses mA and mB which move with velocities vA and vB respectively. The ratio of their kinetic energies (KB : KA) is :
- vB : vA
- 1 : 1
- mB vB : mA vA
- mB : mA
Answer
(1) vB : vA
Solution
initial momentum = 0, so the two parts get equal and opposite momenta
mA vA = mB vB = p
K = 12mv2 = 12pv
KBKA = 12pvB 12pvA = vBvA
KB : KA = vB : vA
Answer: (1)