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Integrals · Question 13

JEE Main 2026 (Online) 2nd April Morning ShiftNumericalHard📈 Topic in 71% papers+4
1

If = 02 3 2 (x2+4 )dx+ 24 2x-4 dx, then 2 is equal to .

Answer

192

Solution

Let f(x)= 2(x2+4), x [0,2 3]: increasing, f(0)=2, f(2 3)= 216=4.

y= 2(x2+4) x= 2y-4, so f-1(y)= 2y-4 on [2,4].

For an increasing f: ab f(x) dx+ f(a)f(b)f-1(y) dy=b f(b)-a f(a)

(the two areas together fill the rectangle up to (b,f(b)) minus the one up to (a,f(a))).

=2 3 4-0 2=8 3

∴ 2=192

Answer: 192

JEE Main 2026 (Online) 2nd April Morning Shift

Keep practising — Integrals

2

The value of 020 ( 4 x+ 4 x )dx is equal to:

  1. 15 2
  2. 25
  3. 15
  4. 25 2
JEE Main 2026 (Online) 2nd April Evening Shift
3

Let f(x)= ( 16x+24x2+2x-15 )dx. If f(4)=14 e(3) and f(7)= e (2 3 ), , N, then + is equal to :

  1. 31
  2. 37
  3. 39
  4. 41
JEE Main 2026 (Online) 2nd April Evening Shift
4

Let f be a polynomial function such that f(x2 + 1) = x4 + 5x2 + 2, for all x R. Then 03 f(x) dx is equal to

  1. 332
  2. 53
  3. 272
  4. 413
JEE Main 2026 (Online) 28th January Morning Shift
5

If ( 1 - 5 2 x 5 x 2 x )dx = f(x) + C, where C is the constant of integration, then f ( 6 ) - f ( 4 ) is equal to

  1. 1 3(26 - 3)
  2. 4 3(8 - 6)
  3. 1 3(26 + 3)
  4. 2 3(4 + 6)
JEE Main 2026 (Online) 28th January Morning Shift
6

The value of r=120 ( | ( 0r x| x|dx ) | ) is .

JEE Main 2026 (Online) 28th January Morning Shift
7

Let f(x) = dxx2/3 + 2x1/2, be such that f(0) = -26 + 24 e(2). If f(1) = a + b e(3), where a, b Z, then a + b is equal to :

  1. -5
  2. -11
  3. -18
  4. -26
JEE Main 2026 (Online) 28th January Evening Shift
8

Let [.] denote the greatest integer function. Then - 2 2 ( 12(3 + [x])3 + [ x] + [ x] ) dx is equal to :

  1. 12 + 5
  2. 11 + 2
  3. 15 + 4
  4. 13 + 1
JEE Main 2026 (Online) 28th January Evening Shift
9

Let f(t) = ( 1 - ( e t)1 - ( e t) ) dt, t > 1. If f (e /2 ) = -e /2 and f (e /4 ) = e /4, then equals

  1. 1 + 2
  2. -1 - 2 2
  3. -1 - 2
  4. -1 + 2
JEE Main 2026 (Online) 24th January Morning Shift
10

If f(x) satisfies the relation f(x) = ex + 01 (y + xex) f(y) dy, then e + f(0) is equal to .

JEE Main 2026 (Online) 24th January Evening Shift
11

Let f(x) = (2 - x2 ) ex ( 1 + x )(1 - x)3/2 dx. If f(0) = 0, then f ( 12 ) is equal to:

  1. 2e - 1
  2. 2e + 1
  3. 3e - 1
  4. 3e + 1
JEE Main 2026 (Online) 23rd January Morning Shift

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