The value of 020 ( 4 x+ 4 x )dx is equal to:
- 15 2
- 25
- 15
- 25 2
Answer
(3) 15
Solution
4x+ 4x=( 2x+ 2x)2-2 2x 2x=1- 12 2 2x
=1- 14(1- 4x)= 34+ 14 4x
020 4x dx= [ 4x4 ]020 =0
020 ( 4x+ 4x )dx= 34 20 =15
Answer: (3)
The value of 020 ( 4 x+ 4 x )dx is equal to:
(3) 15
4x+ 4x=( 2x+ 2x)2-2 2x 2x=1- 12 2 2x
=1- 14(1- 4x)= 34+ 14 4x
020 4x dx= [ 4x4 ]020 =0
020 ( 4x+ 4x )dx= 34 20 =15
Answer: (3)
Let f(x)= ( 16x+24x2+2x-15 )dx. If f(4)=14 e(3) and f(7)= e (2 3 ), , N, then + is equal to :
Let f be a polynomial function such that f(x2 + 1) = x4 + 5x2 + 2, for all x R. Then 03 f(x) dx is equal to
If ( 1 - 5 2 x 5 x 2 x )dx = f(x) + C, where C is the constant of integration, then f ( 6 ) - f ( 4 ) is equal to
The value of r=120 ( | ( 0r x| x|dx ) | ) is .
Let f(x) = dxx2/3 + 2x1/2, be such that f(0) = -26 + 24 e(2). If f(1) = a + b e(3), where a, b Z, then a + b is equal to :
Let [.] denote the greatest integer function. Then - 2 2 ( 12(3 + [x])3 + [ x] + [ x] ) dx is equal to :
Let f(t) = ( 1 - ( e t)1 - ( e t) ) dt, t > 1. If f (e /2 ) = -e /2 and f (e /4 ) = e /4, then equals
If f(x) satisfies the relation f(x) = ex + 01 (y + xex) f(y) dy, then e + f(0) is equal to .
Let f(x) = (2 - x2 ) ex ( 1 + x )(1 - x)3/2 dx. If f(0) = 0, then f ( 12 ) is equal to:
The value of the integral 24 5 24 dx1 + [3] 2x is :