In the given circuit below inductance values of L1, L2 and L3 are same. The magnetic energy stored in the entire circuit is (Ut) and that stored in the L2 inductor is (Ul). Ut/Ul is . (Ignore the mutual inductance if any) [figure]
Answer
6
Solution
L2 and L3 are equal and in parallel ⇒ each carries I2, while L1 carries the full current I.
[figure]
Ut= 12LI2+ 12L ( I2 )2+ 12L ( I2 )2= 12LI2 (1+ 14+ 14 )= 34LI2
Ul= 12L ( I2 )2= 18LI2
∴ UtUl= 3/41/8=6
Answer: 6