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Continuity and Differentiability · Question 9

JEE Main 2026 (Online) 24th January Morning ShiftMCQEasy📈 Topic in 16% papers+4−1
1

Let , R be such that the function f(x) = cases 2 (x2 - 2 ) + 2 x, & x < 1 \ ( + 3)x + ( - ), & x 1 cases be differentiable at all x R. Then 34( + ) is equal to

  1. 48
  2. 84
  3. 36
  4. 24

Answer

(1) 48

Solution

Continuity at x = 1:

2 (1 - 2) + 2 = ( + 3) + ( - )

-2 + 2 = 2 + 3 - 4 - 3 = -3 ...(i)

Differentiability at x = 1: LHD = 4 x + 2 |x=1 = 4 + 2 , RHD = + 3

4 + 2 = + 3 3 + 2 = 3 ...(ii)

Solving (i) and (ii): = 317, = 2117

34( + ) = 34 2417 = 48

Answer: (1)

JEE Main 2026 (Online) 24th January Morning Shift

Keep practising — Continuity and Differentiability

2

Let [t] denote the greatest integer less than or equal to t. If the function f(x) = cases b2 ( 2 [ 2( x + x) x ] ), & x < 0 \ x - 12 2xx3, & x > 0 \ a, & x = 0 cases is continuous at x = 0, then a2 + b2 is equal to :

  1. 12
  2. 58
  3. 34
  4. 916
JEE Main 2026 (Online) 24th January Evening Shift
3

Let f(x) = cases ax2 + 2ax + 34x2 + 4x - 3 & , x - 32, 12 \ b & , x = - 32, 12 cases be continuous at x = - 32. If f f(x) = 75, then x is equal to:

  1. 1.4
  2. 2
  3. 1
  4. 0
JEE Main 2026 (Online) 23rd January Morning Shift
4

If f(x) = cases a|x| + x2 - 2( |x|)( |x|)x & , x 0 \ b & , x = 0 cases is continuous at x = 0, then a + b is equal to :

  1. 1
  2. 2
  3. 0
  4. 4
JEE Main 2026 (Online) 23rd January Evening Shift
5

Let [ ] denote the greatest integer function, and let f(x) = \ 2x, x2 \. Let S = \x (-2, 2) : the function g(x) = |x| [x2 ] is discontinuous at x\. Then x S f(x) equals

  1. 2 - 2
  2. 2 6 - 3 2
  3. 1 - 2
  4. 6 - 2 2
JEE Main 2026 (Online) 22nd January Evening Shift
6

The number of points of discontinuity of the function f(x) = [ x22 ] - [ x], x [0, 4], where [ ] denotes the greatest integer function, is .

JEE Main 2025 (Online) 7th April Morning Shift
7

If the function f(x) = ( x) - ( x) x - x is continuous at x = 0, then f(0) is equal to .

JEE Main 2025 (Online) 7th April Evening Shift
8

Let m and n be the number of points at which the function f(x) = \x, x3, x5, , x21 \, x R, is not differentiable and not continuous, respectively. Then m + n is equal to .

JEE Main 2025 (Online) 4th April Morning Shift
9

Let f(x) = cases (1 + ax)1/x, & x < 0 \ 1 + b, & x = 0 \ (x+4)1/2 - 2(x+c)1/3 - 2, & x > 0 cases be continuous at x = 0. Then ea bc is equal to:

  1. 64
  2. 48
  3. 36
  4. 72
JEE Main 2025 (Online) 3rd April Morning Shift
10

Let f(x) = cases 3x, & x < 0 \ \1 + x + [x], x + 2[x]\, & 0 x 2 \ 5, & x > 2 cases where [.] denotes greatest integer function. If and are the number of points, where f is not continuous and is not differentiable, respectively, then + equals .

JEE Main 2025 (Online) 28th January Morning Shift

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