The kinetic energies of two similar cars A and B are 100 J and 225 J respectively. On applying brakes, car A stops after 1000 m and car B stops after 1500 m. If FA and FB are the forces applied by the brakes on cars A and B respectively, then the ratio of FAFB is
- 13
- 12
- 32
- 23
Answer
(4) 23
Solution
Work-energy theorem: F d = K, so F = Kd
FA = 1001000 = 0.1 N, FB = 2251500 = 0.15 N
FAFB = 0.10.15 = 23
Answer: (4)