In Haber process 30 litres of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end ?
- 20 litres ammonia, 20 litres nitrogen, 20 litres hydrogen
- 10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
- 20 litres ammonia, 10 litres nitrogen, 30 litres hydrogen
- 20 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
Answer
(2) 10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
Solution
N2(g) + 3H2(g) 2NH3(g)
∵ By volume, 1 L of N2 needs 3 L of H2; 30 L of H2 needs only 10 L of N2
⇒ H2 is the limiting reagent; expected NH3 = 23 30 = 20 L
⇒ Actual yield (50%) = 10 L of NH3
⇒ H2 used = 15 L, N2 used = 5 L
∴ Left: H2 = 30 - 15 = 15 L, N2 = 30 - 5 = 25 L, NH3 = 10 L
Answer: (2)