Two point charges q1=3 μC and q2=-4 μC are placed at points (2 i+3 j+3 k ) and ( i+ j+ k ) respectively. Force on charge q2 is N. (Take 14 0=9 109 SI Units)
- (12 i+24 j+24 k ) 10-3
- (4 i+8 j+8 k ) 10-3
- (3 i+6 j+6 k ) 10-3
- (-4 i-8 j-8 k ) 10-3
Answer
(2) (4 i+8 j+8 k ) 10-3
Solution
Vector from q1 to q2: r= ( i+ j+ k )- (2 i+3 j+3 k )=- i-2 j-2 k
| r|= 1+4+4=3 m
F2= 14 0 q1q2r3 r
= 9 109 (3 10-6) (-4 10-6)27 (- i-2 j-2 k )
=-4 10-3 (- i-2 j-2 k )
= (4 i+8 j+8 k ) 10-3 N (directed towards q1: unlike charges attract)
Answer: (2)