A point charge q = 1 is located at a distance 2 cm from one end of a thin insulating wire of length 10 cm having a charge Q = 24 , distributed uniformly along its length, as shown in figure. Force between q and wire is N. (Use : 14 0 = 9 109 N m2/C2) [figure]
Answer
90
Solution
Linear charge density = QL. Take an element dx of the wire at distance x from q (x from d = 2 cm to d + L = 12 cm).
dF = kq dxx2
F = kq dd+L dxx2 = kq ( 1d - 1d + L ) = kqQd(d + L)
F = 9 109 1 10-6 24 10-60.02 0.12
F = 0.2162.4 10-3
F = 90 N
Answer: 90