The electrostatic potential in a charged spherical region of radius r varies as V = ar3 + b, where a and b are constants. The total charge in the sphere of unit radius is a 0. The value of is . (permittivity of vacuum is 0)
- -12
- -8
- -9
- -6
Answer
(1) -12
Solution
Electric field: E = - dVdr = -3ar2 (radial)
Gauss's law for a sphere of radius r: E 4 r2 = q 0
q = 4 0 r2(-3ar2) = -12 a 0 r4
For r = 1: q = -12 a 0
= -12
Answer: (1)