A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be
- 1.4
- 3.0
- 2.8
- 4.4
Answer
(3) 2.8
Solution
Conc. H2SO4 dehydrates both acids:
HCOOH conc. H2SO4 CO + H2O
H2C2O4 conc. H2SO4 CO + CO2 + H2O
Moles of HCOOH = 2.346 = 0.05 mol ⇒ CO formed = 0.05 mol
Moles of H2C2O4 = 4.590 = 0.05 mol ⇒ CO = 0.05 mol and CO2 = 0.05 mol
∵ KOH pellets absorb CO2 (acidic gas) and moisture, only CO remains.
∴ Total CO = 0.05 + 0.05 = 0.1 mol
Mass of CO = 0.1 28
= 2.8 g
Answer: (3)