Some Basic Concepts of Chemistry · Question 28

AIPMT 2014MCQEasy📈 Topic in 38% papers+4−1

When 22.4 litres of H2(g) is mixed with 11.2 litres of Cl2(g), each at S.T.P. the moles of HCl(g) formed is equal to

1 mol of HCl(g)
2 mol of HCl(g)
0.5 mol of HCl(g)
1.5 mol of HCl(g)

Answer

(1) 1 mol of HCl(g)

Solution

H2(g) + Cl2(g) 2HCl(g)

At S.T.P., 22.4 L = 1 mol.

nH2 = 22.422.4 = 1 mol, nCl2 = 11.222.4 = 0.5 mol

H2 and Cl2 react in 1 : 1 ratio, Cl2 is the limiting reagent.

nHCl = 2 0.5 = 1 mol

Answer: (1)

AIPMT 2014

Keep practising — Some Basic Concepts of Chemistry

1.0 g of magnesium is burnt with 0.56 g O2 in a closed vessel. Which reactant is left in excess and how much ? (At. wt. Mg = 24, O = 16)

Mg, 0.16 g
O2, 0.16 g
Mg, 0.44 g
O2, 0.28 g

AIPMT 2014

6.02 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is

0.001 M
0.1 M
0.02 M
0.01 M

NEET 2013

How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO3? The concentrated acid is 70\% HNO3.

70.0 g conc. HNO3
54.0 g conc. HNO3
45.0 g conc. HNO3
90.0 g conc. HNO3

NEET 2013

In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine)

X2Cl2
XCl2
XCl4
X2Cl

NEET 2013 (Karnataka)

Which has the maximum number of molecules among the following ?

44 g CO2
48 g O3
8 g H2
64 g SO2

AIPMT 2011 (Mains)

The number of atoms in 0.1 mol of a triatomic gas is ( NA = 6.02 1023 mol-1)

6.026 1022
1.806 1023
3.600 1023
1.800 1022

AIPMT 2010 (Prelims)

25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na+ and carbonate ions, CO32- are respectively (Molar mass of Na2CO3 = 106 g mol-1)