An artillery piece of mass M1 fires a shell of mass M2 horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is:
- M1/(M1+M2)
- M2M1
- M1M2
- M2/(M1+M2)
Answer
(2) M2M1
Solution
Initial momentum =0 M1v1=M2v2=p (equal and opposite momenta)
K= p22M K 1M for the same p
K1K2= p2/2M1p2/2M2= M2M1
Answer: (2)