The resistance of a wire is 'R' ohm. If it is melted and stretched to 'n' times its original length, its new resistance will be
- Rn
- n2R
- Rn2
- nR
Answer
(2) n2R
Solution
R = lA and the volume Al stays constant on melting and recasting.
If l' = nl, then A' = An
R' = (nl)A/n = n2 lA
R' = n2R
Answer: (2)