The charge flowing through a resistance R varies with time t as Q = at - bt2, where a and b are positive constants. The total heat produced in R is
- a3R2b
- a3Rb
- a3R6b
- a3R3b
Answer
(3) a3R6b
Solution
Current through the resistance: I = dQdt = a - 2bt
Current flows (in one direction) until I = 0, i.e. up to t0 = a2b.
Heat produced: H = 0t0 I2R dt = R 0a/2b (a - 2bt)2 dt
H = R [ -(a - 2bt)36b ]0a/2b
H = R [0 + a36b ] = a3R6b
Answer: (3)