When 1 dm3 of CO2 gas is passed over hot coke, the volume of gaseous mixture after complete reaction at STP becomes 1.4 dm3. The composition of the gaseous mixture at STP is :
- 0.6 dm3 of CO, 0.8 dm3 of CO2
- 0.8 dm3 of CO, 0.8 dm3 of CO2
- 0.6 dm3 of CO, 0.4 dm3 of CO2
- 0.8 dm3 of CO, 0.6 dm3 of CO2
Answer
(4) 0.8 dm3 of CO, 0.6 dm3 of CO2
Solution
CO2(g) + C(s) 2CO(g)
Let x dm3 of CO2 react ⇒ 2x dm3 of CO is formed and (1 − x) dm3 of CO2 is left.
∴ Total volume = (1 − x) + 2x = 1 + x = 1.4 ⇒ x = 0.4
⇒ CO = 2 × 0.4 = 0.8 dm3 and CO2 = 1 − 0.4 = 0.6 dm3
Answer: (4)