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Probability (Class 12) · Question 10

JEE Main 2026 (Online) 21st January Evening ShiftMCQMedium📈 Topic in 10% papers+4−1
1

A random variable X takes values 0, 1, 2, 3 with probabilities 2a+130, 8a-130, 4a+130, b respectively, where a, b R. Let and respectively be the mean and standard deviation of X such that 2 + 2 = 2. Then ab is equal to:

  1. 12
  2. 60
  3. 30
  4. 3

Answer

(2) 60

Solution

Sum of probabilities = 1:

(2a + 1) + (8a - 1) + (4a + 1)30 + b = 1

14a + 130 + b = 1 ...(i)

2 = E(X2) - 2 E(X2) = 2 + 2 = 2

E(X2) = 0 + 1 8a - 130 + 4 4a + 130 + 9b = 2

24a + 330 + 9b = 2 ...(ii)

(ii) − 9 × (i): 24a + 3 - 126a - 930 = 2 - 9

-102a - 6 = -210 a = 2

From (i): b = 1 - 2930 = 130

(Probabilities 530, 1530, 930, 130 are all valid.)

ab = 2 30 = 60

Answer: (2)

JEE Main 2026 (Online) 21st January Evening Shift

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