A random variable X takes values 0, 1, 2, 3 with probabilities 2a+130, 8a-130, 4a+130, b respectively, where a, b R. Let and respectively be the mean and standard deviation of X such that 2 + 2 = 2. Then ab is equal to:
- 12
- 60
- 30
- 3
Answer
(2) 60
Solution
Sum of probabilities = 1:
(2a + 1) + (8a - 1) + (4a + 1)30 + b = 1
14a + 130 + b = 1 ...(i)
2 = E(X2) - 2 E(X2) = 2 + 2 = 2
E(X2) = 0 + 1 8a - 130 + 4 4a + 130 + 9b = 2
24a + 330 + 9b = 2 ...(ii)
(ii) − 9 × (i): 24a + 3 - 126a - 930 = 2 - 9
-102a - 6 = -210 a = 2
From (i): b = 1 - 2930 = 130
(Probabilities 530, 1530, 930, 130 are all valid.)
ab = 2 30 = 60
Answer: (2)