Let three vectors a = i + 4 j + 2 k, b = 5 i + 3 j + 4 k, c = x i + y j + z k form a triangle such that c = a - b and the area of the triangle is 5 6. If is a positive real number, then | c|2 is equal to:
- 14
- 12
- 16
- 10
Answer
(1) 14
Solution
Since a and b are two sides of the triangle, area = 12| a b|
a b = vmatrix i & j & k\ & 4 & 2\ 5 & 3 & 4 vmatrix = 10 i - (4 - 10) j + (3 - 20) k
12| a b| = 5 6 100 + (4 - 10)2 + (3 - 20)2 = 600
25 2 - 200 = 0 = 8 (as > 0)
Hence c = a - b = 3 i + j - 2 k, so | c|2 = 9 + 1 + 4 = 14
Answer: (1)