Let a = 2 i - 3 j + 4 k, b = 3 i + 4 j - 5 k and a vector c be such that a ( b + c ) + b c = i + 8 j + 13 k. If a c = 13, then (24 - b c ) is equal to .
Answer
46
Solution
Let d = i + 8 j + 13 k; the condition is a b + a c + b c = d.
Here a b = 6 - 12 - 20 = -26, | a|2 = 29, | b|2 = 50 and a c = 13.
Take the cross product of a with both sides and open every term by the vector triple product a ( p q) = ( a q) p - ( a p) q:
(-26 a - 29 b) + (13 a - 29 c) + (13 b + 26 c) = a d, i.e. 13 a + 16 b + 3 c = d a
Now take the dot product with b, so that c appears only as b c:
13( a b) + 16| b|2 + 3( b c) = [ d a b]
where [ d a b] = vmatrix 1 & 8 & 13 \ 2 & -3 & 4 \ 3 & 4 & -5 vmatrix = -1 + 176 + 221 = 396
This gives -338 + 800 + 3( b c) = 396, so b c = -22.
Therefore 24 - b c = 24 + 22 = 46
Answer: 46