Let a = 4 i - j + k, b = 11 i - j + k and c be a vector such that ( a + b) c = c (-2 a + 3 b). If (2 a + 3 b) c = 1670, then | c|2 is equal to:
- 1600
- 1618
- 1627
- 1609
Answer
(2) 1618
Solution
( a + b) c + (-2 a + 3 b) c = 0 (4 b - a) c = 0
cross product zero parallel: c = (4 b - a) = (40 i - 3 j + 3 k)
2 a + 3 b = 41 i - 5 j + 5 k
(1640 + 15 + 15) = 1670 = 1
| c|2 = 402 + 32 + 32 = 1618
Answer: (2)