If A(3, 1, -1), B ( 53, 73, 13 ), C(2, 2, 1) and D ( 103, 23, -13 ) are the vertices of a quadrilateral ABCD, then its area is
- 4 23
- 2 23
- 5 23
- 2 2
Answer
(1) 4 23
Solution
Area of a quadrilateral = 12 | AC BD | (AC, BD = diagonals)
AC = - i + j + 2 k, BD = 53 i - 53 j - 23 k
AC BD = vmatrix i & j & k \ -1 & 1 & 2 \ 53 & - 53 & - 23 vmatrix
= 83 i + 83 j + 0 k
Area = 12 8 23 = 4 23
Answer: (1)