A solid cylinder having radius R and length L is slipping on a rough horizontal plane. At time t=0 the cylinder has a translational velocity v0=49 m/s, perpendicular to its axis and a rotational velocity v0/4R about the centre. The time taken by the cylinder to start rolling is seconds. (coefficient of kinetic friction K=0.25 and g=9.8 m/s2)
- 15
- 5
- 10
- 7.5
Answer
(2) 5
Solution
[figure]
At t=0: 0R= v04<v0 the lowest point slides forward, so kinetic friction f= Kmg acts backward
Translation: a= Kg (retarding) v=v0- Kgt
Rotation: = fRI= KmgR 12mR2= 2 KgR R= v04+2 Kgt
Pure rolling starts when v= R:
v0- Kgt= v04+2 Kgt
3 Kgt= 3v04
t= v04 Kg= 494 0.25 9.8=5 s
Answer: (2)