An object of uniform density rolls up the curved path with the initial velocity v0 as shown in the figure. If the maximum height attained by an object is 7v0210g (g = acceleration due to gravity), the object is a . [figure]
- solid cylinder
- ring
- disc
- solid sphere
Answer
(4) solid sphere
Solution
Rolling without slipping: friction does no work, so mechanical energy is conserved.
KE= 12mv02+ 12I 2= 12mv02 (1+ k2R2 )
At the maximum height the body is at rest: 12mv02 (1+ k2R2 )=mgh
h= v022g (1+ k2R2 )= 7v0210g
1+ k2R2= 75 k2R2= 25
k2R2: ring =1, disc / solid cylinder = 12, solid sphere = 25
The object is a solid sphere.
Answer: (4)