A solid sphere of radius 4 cm and mass 5 kg is rotating (rotation axis is passing through the centre of the sphere) with an angular velocity of 1200 rpm. It is brought to rest in 10 s by applying a constant torque. The torque applied and the number of rotations it made before it comes to rest are and respectively.
- 0.128 Nm, 100
- 0.0128 Nm, 50
- 0.128 Nm, 50
- 0.0128 Nm, 100
Answer
(4) 0.0128 Nm, 100
Solution
I= 25MR2= 25 5 (0.04)2=3.2 10-3 kg m2
0=1200 rpm=1200 2 60=40 rad/s
Uniform retardation to rest in 10 s:
= 0t= 40 10=4 rad/s2
∴ =I =3.2 10-3 4 =0.0128 N m
Angle turned: = 0+02 t= 40 2 10=200 rad
⇒ Number of rotations = 200 2 =100
Answer: (4)