Suppose the charge of a proton and an electron differ slightly. One of them is -e, the other is (e + e). If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then e is of the order of [Given : mass of hydrogen mh = 1.67 10-27 kg]
- 10-23 C
- 10-37 C
- 10-47 C
- 10-20 C
Answer
(2) 10-37 C
Solution
Net charge on each hydrogen atom = (e + e) - e = e
For zero net force, electrostatic repulsion = gravitational attraction:
14 0 ( e)2d2 = G mh2d2
e = mh 4 0 G
= 1.67 10-27 6.67 10-119 109
= 1.67 10-27 8.6 10-11
1.4 10-37 C
e is of the order of 10-37 C.
Answer: (2)