For a reaction, N2O5(g) 2NO2(g) + 12O2(g) in a constant volume container, no products were present initially. The final pressure of the system when 50\% of reaction gets completed is
- 5/2 times of initial pressure
- 7/2 times of initial pressure
- 7/4 times of initial pressure
- 5 times of initial pressure
Answer
(3) 7/4 times of initial pressure
Solution
At constant V,T: p n.
N2O5 left = p02, NO2=2 p02=p0, O2= 12 p02= p04
ptotal= p02+p0+ p04= 74p0
Answer: (3)