In acidic medium, H2O2 changes Cr2O72- to CrO5 which has two (-O-O-) bonds. Oxidation state of Cr in CrO5 is
- +5
- +3
- +6
- -10
Answer
(3) +6
Solution
CrO5 (chromium peroxide, butterfly structure) has one Cr=O bond and two peroxide (-O-O-) linkages.
Oxide oxygen: 1 (-2) = -2; peroxide oxygens: 4 (-1) = -4
Let the oxidation state of Cr be x:
x + (-2) + (-4) = 0
⇒ x = +6
Answer: (3)