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20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is 10-2 M. (Nearest integer)
57
Moles: 2 20+0.5 400=240 mmol in 420 mL
M= 240420=0.5714=57.14 10-2 M
Answer: 57
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