The correct order of total number of atoms present in (A) 2 moles of cyclohexane (B) 684 g of sucrose (C) 90.8 L of dihydrogen at STP is :
- C > A > B
- C > B > A
- B > C > A
- B > A > C
Answer
(4) B > A > C
Solution
Number of atoms = moles of molecules × atoms per molecule (× NA, common to all)
(A) Cyclohexane, C6H12 (6 + 12 = 18 atoms per molecule)
⇒ atoms = 2 × 18 = 36 mol of atoms
(B) Sucrose, C12H22O11 (45 atoms per molecule), M = 342 g mol-1
⇒ n = 684342 = 2 mol ⇒ atoms = 2 × 45 = 90 mol of atoms
(C) Dihydrogen, H2; at STP (1 bar, 273.15 K) molar volume = 22.7 L
⇒ n = 90.822.7 = 4 mol ⇒ atoms = 4 × 2 = 8 mol of atoms
∴ B (90 NA) > A (36 NA) > C (8 NA)
Answer: (4)