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Some Basic Concepts of Chemistry · Question 10

JEE Main 2026 (Online) 28th January Evening ShiftMCQMedium📈 Topic in 42% papers+4−1
1

For the given reaction; CaCO3 + 2HCl CaCl2 + H2O + CO2 If 90 g CaCO3 is added to 300 mL of HCl which contains 38.55% HCl by mass and has density 1.13 g mL-1, then which of the following option is correct? Given molar mass of H, Cl, Ca and O are 1, 35.5, 40 and 16 g mol-1 respectively.

  1. 64.97 g of HCl remains unreacted
  2. 60.32 g of HCl remains unreacted
  3. 32.85 g of CaCO3 remains unreacted
  4. 97.30 g of HCl reacted

Answer

(1) 64.97 g of HCl remains unreacted

Solution

Mass of HCl solution = 300 1.13 = 339 g

Mass of HCl = 339 38.55100 = 130.68 g

nHCl = 130.6836.5 = 3.58 mol

nCaCO3 = 90100 = 0.9 mol (molar mass = 40 + 12 + 48 = 100)

1 mol CaCO3 needs 2 mol HCl, 0.9 mol needs 1.8 mol HCl (< 3.58 mol)

CaCO3 is the limiting reagent and is used up completely.

HCl reacted = 1.8 36.5 = 65.70 g

HCl unreacted = 130.68 - 65.70 = 64.98 g 64.97 g

Answer: (1)

JEE Main 2026 (Online) 28th January Evening Shift

Keep practising — Some Basic Concepts of Chemistry

2

A student has planned to prepare acetanilide from aniline using acetic anhydride. The student has started from 9.3 g of aniline. However, the student has managed to obtain 11 g of dry acetanilide. The % yield of this reaction is :-

  1. 59.5\%
  2. 72.5\%
  3. 97.5\%
  4. 81.5\%
JEE Main 2026 (Online) 24th January Evening Shift
3

x mg of pure HCl was used to make an aqueous solution. 25.0 mL of 0.1 M Ba(OH)2 solution is used when the HCl solution was titrated against it. The numerical value of x is 10-1. (Nearest integer) Given : Molar mass of HCl and Ba(OH)2 are 36.5 and 171.0 g mol-1 respectively.

JEE Main 2026 (Online) 23rd January Morning Shift
4

In the reaction, 2Al(s) + 6HCl(aq) 2Al3+(aq) + 6Cl-(aq) + 3H2(g)

  1. 12 L HCl(aq) is consumed for every 6 L H2(g) produced.
  2. 11.2 L H2(g) at STP is produced for every mole of HCl consumed.
  3. 33.6 L H2(g) is produced regardless of temperature and pressure for every mole of Al that reacts.
  4. 67.2 L H2(g) at STP is produced for every mole of Al that reacts.
JEE Main 2026 (Online) 22nd January Morning Shift
5

At T(K), 100 g of 98\% H2SO4 (w/w) aqueous solution is mixed with 100 g of 49\% H2SO4 (w/w) aqueous solution. What is the mole fraction of H2SO4 in the resultant solution? (Given : Atomic mass H = 1 u; S = 32 u; O = 16 u). (Assume that temperature after mixing remains constant)

  1. 0.9
  2. 0.663
  3. 0.1
  4. 0.337
JEE Main 2026 (Online) 22nd January Evening Shift
6

A + 2B AB2 36.0 g of 'A' (Molar mass : 60 g mol-1) and 56.0 g of 'B' (Molar mass : 80 g mol-1) are allowed to react. Which of the following statements are correct ? Choose the correct answer from the options given below :

  1. A and C Only
  2. A and B Only
  3. C and D Only
  4. B and D Only
JEE Main 2026 (Online) 22nd January Evening Shift
7

14.0 g of calcium metal is allowed to react with excess HCl at 1.0 atm pressure and 273 K. Which of the following statements is incorrect? [Given : Molar mass in g mol-1 of Ca – 40, Cl – 35.5, H – 1]

  1. The limiting reagent is calcium metal.
  2. 33.3 g of CaCl2 is produced.
  3. 7.84 L of H2 gas is evolved.
  4. 0.35 mol of H2 gas is evolved.
JEE Main 2026 (Online) 21st January Morning Shift
8

80 mL of a hydrocarbon on mixing with 264 mL of oxygen in a closed U-tube undergoes complete combustion. The residual gases after cooling to 273 K occupy 224 mL. When the system is treated with KOH solution, the volume decreases to 64 mL. The formula of the hydrocarbon is :

  1. C2H2
  2. C2H4
  3. C4H10
  4. C2H6
JEE Main 2026 (Online) 21st January Morning Shift
9

Aqueous HCl reacts with MnO2(s) to form MnCl2(aq), Cl2(g), and H2O(l). What is the weight (in g) of Cl2 liberated when 8.7 g of MnO2(s) is reacted with excess aqueous HCl solution? (Given Molar mass in g mol-1 Mn = 55, Cl = 35.5, O = 16, H = 1)

  1. 14.2
  2. 21.3
  3. 7.1
  4. 71
JEE Main 2026 (Online) 21st January Evening Shift
10

20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol-1)

JEE Main 2025 (Online) 8th April Evening Shift
11

Thyroxine, the hormone, has the structure given below [figure] The percentage of iodine in thyroxine is %. (nearest integer) (Given molar mass in g mol-1 C : 12, H : 1, O : 16, N : 14, I : 127)

JEE Main 2025 (Online) 7th April Morning Shift

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