Consider the following aqueous solutions. I. 2.2 g glucose in 125 mL of solution. II. 1.9 g calcium chloride in 250 mL of solution. III. 9.0 g urea in 500 mL of solution. IV. 20.5 g aluminium sulphate in 750 mL of solution. The correct increasing order of boiling point of these solutions will be : [Given : Molar mass in g mol-1 : H = 1, C = 12, N = 14, O = 16, Cl = 35.5, Ca = 40, Al = 27 and S = 32]
- III < I < II < IV
- II < III < IV < I
- II < III < I < IV
- I < II < III < IV
Answer
(4) I < II < III < IV
Solution
Tb = iKbm; for these dilute aqueous solutions m ≈ molarity, so compare i M.
I. Glucose (180): 2.2/1800.125 = 0.098 M, i = 1 0.098
II. CaCl2 (111): 1.9/1110.250 = 0.068 M, i = 3 0.205
III. Urea (60): 9.0/600.500 = 0.30 M, i = 1 0.30
IV. Al2(SO4)3 (342): 20.5/3420.750 = 0.080 M, i = 5 0.40
Boiling point: I < II < III < IV
Answer: (4)