In which of the following arrangements the given sequence is not strictly according to the property indicated against it?
- HF < HCl < HBr < HI : increasing acidic strength
- H2O < H2S < H2Se < H2Te : increasing pKa values
- NH3 < PH3 < AsH3 < SbH3 : increasing acidic character
- CO2 < SiO2 < SnO2 < PbO2 : increasing oxidising power
Answer
(2) H2O < H2S < H2Se < H2Te : increasing pKa values
Solution
(1) Down group 17, the H–X bond dissociation enthalpy decreases ⇒ acidic strength HF < HCl < HBr < HI ⇒ correct.
(2) As per NCERT, the acidic character of hydrides of group 16 increases from H2O to H2Te (H–E bond enthalpy decreases).
∵ A stronger acid has a lower pKa ⇒ pKa decreases: H2O > H2S > H2Se > H2Te
∴ The given order of increasing pKa is not correct.
(3) Down group 15, the E–H bond becomes weaker ⇒ acidic character NH3 < PH3 < AsH3 < SbH3 ⇒ correct.
(4) Down group 14, the +4 state becomes less stable (inert pair effect) ⇒ oxidising power of MO2 increases; PbO2 is a strong oxidising agent ⇒ correct.
Answer: (2)