The mean and variance of n observations are 8 and 16, respectively. If the sum of the first (n-1) observations is 48 and the sum of squares of the first (n-1) observations is 496, then the value of n is :
- 21
- 16
- 13
- 7
Answer
(4) 7
Solution
i=1nxi=8n xn=8n-48
2= xi2n- x2 i=1nxi2=n(16+64)=80n
496+(8n-48)2=80n
64n2-848n+2800=0 4n2-53n+175=0
(n-7)(4n-25)=0 n=7 or 254
n is a natural number, n=7
(Check: x7=8; xi2=496+64=560=80 7)
Answer: (4)