The mean and variance of 10 observations are 9 and 34.2, respectively. If 8 of these observations are 2, 3, 5, 10, 11, 13, 15, 21, then the mean deviation about the median of all the 10 observations is
- 7
- 4
- 5
- 6
Answer
(3) 5
Solution
Let the other two observations be a and b.
Sum = 10 × 9 = 90; sum of the 8 given = 80 a + b = 10
xi210 - 92 = 34.2 xi2 = 1152
Squares of the 8 given = 4 + 9 + 25 + 100 + 121 + 169 + 225 + 441 = 1094
a2 + b2 = 58
ab = (a + b)2 - (a2 + b2)2 = 100 - 582 = 21
a, b = 3, 7
Data in order: 2, 3, 3, 5, 7, 10, 11, 13, 15, 21
Median = 7 + 102 = 8.5
|xi - 8.5| = 6.5 + 5.5 + 5.5 + 3.5 + 1.5 + 1.5 + 2.5 + 4.5 + 6.5 + 12.5 = 50
M.D. about median = 5010 = 5
Answer: (3)