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Coordination Compounds · Question 83

AIPMT 2004MCQEasy📈 Topic in 12% papers+4−1
1

Considering H2O as a weak field ligand, the number of unpaired electrons in [Mn(H2O)6]2+ will be (atomic number of Mn = 25)

  1. three
  2. five
  3. two
  4. four

Answer

(2) five

Solution

Mn (Z = 25): [Ar] 3d54s2 Mn2+: [Ar] 3d5

H2O is a weak field ligand, o < P and the electrons do not pair.

Configuration t2g3eg2 (high spin)

Number of unpaired electrons = 5

Answer: (2)

AIPMT 2004

Keep practising — Coordination Compounds

2

Which of the following does not have a metal carbon bond?

  1. Al(OC2H5)3
  2. C2H5MgBr
  3. K[Pt(C2H4)Cl3]
  4. Ni(CO)4
AIPMT 2004
3

In an octahedral structure, the pair of d orbitals involved in d2sp3 hybridisation is

  1. dx2-y2, dz2
  2. dxz, dx2-y2
  3. dz2, dxz
  4. dxy, dyz
AIPMT 2004
4

Which of the following is considered to be an anticancer species?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2004
5

Vitamin B12 contains

  1. Fe(II)
  2. Co(III)
  3. Zn(II)
  4. Ca(II)
AIPMT 2003
6

The number of unpaired electrons in the complex ion [CoF6]3- is (Atomic no. : Co = 27)

  1. 2
  2. 3
  3. 4
  4. zero
AIPMT 2003
7

Among the following which is not the -bonded organometallic compound?

  1. K[PtCl3( 2-C2H4)]
  2. Fe( 5-C5H5)2
  3. Cr( 6-C6H6)2
  4. (CH3)4Sn
AIPMT 2003
8

Atomic number of Cr and Fe are respectively 24 and 26, which of the following is paramagnetic with the spin of electron?

  1. [Cr(CO)6]
  2. [Fe(CO)5]
  3. [Fe(CN)6]4-
  4. [Cr(NH3)6]3+
AIPMT 2002
9

The hypothetical complex chloro diaquatriammine cobalt(III) chloride can be represented as

  1. [CoCl(NH3)3(H2O)2]Cl2
  2. [Co(NH3)3(H2O)Cl3]
  3. [Co(NH2)3(H2O)2Cl]
  4. [Co(NH3)3(H2O)3]Cl3
AIPMT 2002
10

In the silver plating of copper, K[Ag(CN)2] is used instead of AgNO3. The reason is

  1. a thin layer of Ag is formed on Cu
  2. more voltage is required
  3. Ag+ ions are completely removed from solution
  4. less availability of Ag+ ions, as Cu cannot displace Ag from [Ag(CN)2]- ion.
AIPMT 2002
11

CuSO4 when reacts with KCN forms CuCN, which is insoluble in water. It is soluble in excess of KCN, due to formation of the following complex

  1. K2[Cu(CN)4]
  2. K3[Cu(CN)4]
  3. CuCN2
  4. Cu[KCu(CN)4]
AIPMT 2002

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