Acetone is treated with excess of ethanol in the presence of hydrochloric acid. The product obtained is
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Answer
(4) [figure]
Solution
As per NCERT, ketones react with alcohols in the presence of dry HCl gas to form a hemiketal first and then a ketal (with excess alcohol).
(CH3)2C=O [dry HCl]C2H5OH(CH3)2C(OH)OC2H5 [dry HCl]C2H5OH(CH3)2C(OC2H5)2+H2O
With excess ethanol the product is the ketal, 2,2-diethoxypropane.
Answer: (4)