[figure] The incorrect statement regarding the given structure is
- can be oxidized to a dicarboxylic acid with Br2 water
- despite the presence of -CHO does not give Schiff's test
- will coexist in equilibrium with 2 other cyclic structures
- has 4 asymmetric carbon atoms
Answer
(1) can be oxidized to a dicarboxylic acid with Br2 water
Solution
[figure]
(1): Br2 water (mild) oxidises only –CHO, giving gluconic acid, a monocarboxylic acid (a dicarboxylic acid needs HNO3), so (1) is incorrect
(2): glucose exists mainly as a cyclic hemiacetal with no free –CHO, so it gives no Schiff's test; (2) is correct
(3): the open chain is in equilibrium with α- and β-D-glucopyranose, so (3) is correct
(4): C-2 to C-5 are chiral (marked ), i.e. 4 asymmetric carbons, so (4) is correct
Answer: (1)